Understanding the reactions of lime with water and carbon dioxide is important for many chemistry concepts. The solubility characteristics of the products are key to interpreting the given scenario.
The reaction of calcium oxide (CaO) with water forms calcium hydroxide ('A'):
\[ \text{CaO}(s) + \text{H}_2\text{O}(l) \rightarrow \text{Ca(OH)}_2(aq) \]
The product, calcium hydroxide, is known as slaked lime, and its aqueous solution is called lime water.
The reaction of calcium hydroxide with carbon dioxide forms calcium carbonate ('B'):
\[ \text{Ca(OH)}_2(aq) + \text{CO}_2(g) \rightarrow \text{CaCO}_3(s) + \text{H}_2\text{O}(l) \]
The product, calcium carbonate, is insoluble in water.
When calcium carbonate reacts with more water and carbon dioxide, it forms calcium hydrogencarbonate, which is soluble in water:
\[ \text{CaCO}_3(s) + \text{H}_2\text{O}(l) + \text{CO}_2(g) \rightarrow \text{Ca(HCO}_3\text{)}_2(aq) \]
The substance 'A' is calcium hydroxide (slaked lime).
Observe the following data given in the table. (\(K_H\) = Henry's law constant)
| Gas | CO₂ | Ar | HCHO | CH₄ |
|---|---|---|---|---|
| \(K_H\) (k bar at 298 K) | 1.67 | 40.3 | \(1.83 \times 10^{-5}\) | 0.413 |
The correct order of their solubility in water is
Match List I with List II:
Choose the correct answer from the options given below:
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is: