Step 1: Understanding the Problem
The given equations are both first-order linear PDEs for \( u(x, t) \) and \( v(x, t) \). For \( u(x, t) \), the solution involves standard methods for solving first-order linear PDEs, and the form of the solution satisfies \( |u(x,t)| \leq e^t \) as the exponential growth is bounded by \( e^t \).
Step 2: Analyzing \( v(x, t) \)
The equation for \( v(x, t) \) is nonlinear due to the \( v^2 \) term. This type of nonlinearity can cause the solution to become undefined for certain values of \( x \) and \( t \), as the solution may blow up.
Step 3: Evaluating \( u(2\pi, \pi) \)
Given the structure of the equation for \( u(x,t) \), evaluating \( u(2\pi, \pi) \) gives \( -e^\pi \), as it follows the solution pattern for this type of equation.
Step 4: Conclusion
Thus, the correct answers are \( \boxed{A} \), \( \boxed{B} \), and \( \boxed{D} \).
Final Answer
\[
\boxed{A} \quad |u(x,t)| \leq e^t \text{ for all } x \in \mathbb{R} \text{ and for all } t > 0
\]
\[
\boxed{B} \quad v(x, 1) \text{ is not defined for certain values of } x \in \mathbb{R}
\]
\[
\boxed{D} \quad u(2\pi, \pi) = -e^\pi
\]