>
Exams
>
Mathematics
>
Arithmetic Progression
>
let tn n 1 2 3 be the nth term of the a p 5 8 11 t
Question:
Let t
n
, n = 1,2,3,... be the n
th
term of the A.P. 5, 8, 11,.... Then the value of n for which t
n
= 305 is
KEAM - 2021
KEAM
Updated On:
Jun 10, 2024
101
100
103
99
95
Hide Solution
Verified By Collegedunia
The Correct Option is
A
Solution and Explanation
The correct option is (A): 101
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Arithmetic Progression
Assertion (A): The sum of the first fifteen terms of the AP $21, 18, 15, 12, \dots$ is zero.
Reason (R): The sum of the first $n$ terms of an AP with first term $a$ and common difference $d$ is given by: \[ S_n = \frac{n}{2} \left[ a + (n - 1) d \right]. \]
CBSE Class X - 2024
Mathematics
Arithmetic Progression
View Solution
The sum of the first three terms of an AP is 30 and the sum of the last three terms is 36. If the first term is 9, then the number of terms is :
CBSE Class X - 2024
Mathematics
Arithmetic Progression
View Solution
How many terms of the $A.P.$ $27, 24, 21, . . .$ must be taken so that their sum is 105? Which term of the A.P. is zero?
CBSE Class X - 2024
Mathematics
Arithmetic Progression
View Solution
In an A.P., if \(a = 8\) and \(a_{10} = -19\), then value of \(d\) is:
CBSE Class X - 2024
Mathematics
Arithmetic Progression
View Solution
Assertion (A): The sum of the first fifteen terms of the AP $21, 18, 15, 12, \dots$ is zero.
Reason (R): The sum of the first $n$ terms of an AP with first term $a$ and common difference $d$ is given by: \[ S_n = \frac{n}{2} \left[ a + (n - 1) d \right]. \]
CBSE Class X - 2024
Mathematics
Arithmetic Progression
View Solution
View More Questions
Questions Asked in KEAM exam
A Spherical ball is subjected to a pressure of 100 atmosphere. If the bulk modulus of the ball is 10
11
N/m
2
,then change in the volume is:
KEAM - 2023
mechanical properties of solids
View Solution
Two identical solid spheres,each of radius 10cm,are kept in contact. If the mass of inertia of this system about the tangent passing through the point of contact is 0. Then mass of each sphere is:
KEAM - 2023
System of Particles & Rotational Motion
View Solution
The value of a(≠0) for which the equation
\(\frac{1}{2}(x-2)^2+1=\sin(\frac{a}{x})\)
holds is/are
KEAM - 2023
Trigonometric Functions
View Solution
\(∫xlog(1+x^2)dx=\)
?
KEAM - 2023
Integration by Parts
View Solution
A uniform thin rod of mass 3kg has a length of 1m. If a point mass of 1kg is attached to it at a distance of 40cm from its center,the center of mass shifts by a distance of:
KEAM - 2023
System of Particles & Rotational Motion
View Solution
View More Questions