>
Exams
>
Mathematics
>
Relations and functions
>
let the function f r rightarrow r be defined by f
Question:
Let the function
f
:
R
β
R
f: R \rightarrow R
f
:
R
β
R
be defined by
f
(
x
)
=
x
3
β
x
2
+
(
x
β
1
)
sin
β‘
x
f(x)=x^{3}-x^{2}+(x-1) \sin x
f
(
x
)
=
x
3
β
x
2
+
(
x
β
1
)
sin
x
and let
g
:
R
β
R
g: R \rightarrow R
g
:
R
β
R
be an arbitrary function. Let
f
g
:
R
β
R
f g: R \rightarrow R
f
g
:
R
β
R
be the product function defined by
(
f
,
g
)
(
x
)
=
f
(
x
)
g
(
x
)
(f, g)(x)=f(x) g(x)
(
f
,
g
)
(
x
)
=
f
(
x
)
g
(
x
)
. Then which of the following statements is/are TRUE?
JEE Advanced - 2020
JEE Advanced
Updated On:
Aug 6, 2024
If
g
g
g
is continuous at
x
=
1
x=1
x
=
1
, then
f
g
f g
f
g
is differentiable at
x
=
1
x=1
x
=
1
If
f
g
f g
f
g
is differentiable at
x
=
1
x=1
x
=
1
, then
g
g
g
is continuous at
x
=
1
x=1
x
=
1
If
g
g
g
is differentiable at
x
=
1
x=1
x
=
1
, then
f
g
f g
f
g
is differentiable at
x
=
1
x=1
x
=
1
If
f
g
f g
f
g
is differentiable at
x
=
1
x=1
x
=
1
, then
g
g
g
is differentiable at
x
=
1
x=1
x
=
1
Hide Solution
Verified By Collegedunia
The Correct Option is
A,
C
Solution and Explanation
(A) If
g
g
g
is continuous at
x
=
1
x=1
x
=
1
, then
f
g
f g
f
g
is differentiable at
x
=
1
x=1
x
=
1
(B) If
g
g
g
is differentiable at
x
=
1
x=1
x
=
1
, then
f
g
f g
f
g
is differentiable at
x
=
1
x=1
x
=
1
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Relations and functions
Let
L
1
:
x
β
1
1
=
y
β
2
β
1
=
z
β
1
β
1
a
n
d
L
2
:
x
+
1
1
=
y
β
2
2
=
z
β
2
2
L_1 : \frac{x-1}{1} = \frac{y-2}{-1} = \frac{z-1}{-1} \quad {and} \quad L_2 : \frac{x+1}{1} = \frac{y-2}{2} = \frac{z-2}{2}
L
1
β
:
1
x
β
1
β
=
β
1
y
β
2
β
=
β
1
z
β
1
β
an
d
L
2
β
:
1
x
+
1
β
=
2
y
β
2
β
=
2
z
β
2
β
be two lines. Let
L
3
L_3
L
3
β
be a line passing through the point
(
Ξ±
,
Ξ²
,
Ξ³
)
(\alpha, \beta, \gamma)
(
Ξ±
,
Ξ²
,
Ξ³
)
and be perpendicular to both
L
1
L_1
L
1
β
and
L
2
L_2
L
2
β
. If
L
3
L_3
L
3
β
intersects
L
1
L_1
L
1
β
where
5
x
β
11
y
β
8
z
=
1
5x - 11y - 8z = 1
5
x
β
11
y
β
8
z
=
1
, then
5
x
β
11
y
β
8
z
5x - 11y - 8z
5
x
β
11
y
β
8
z
equals:
JEE Main - 2025
Mathematics
Relations and functions
View Solution
Let the position vectors of three vertices of a triangle be
p
β
=
4
i
^
+
j
^
β
3
k
^
\overrightarrow{p} = 4\hat{i} + \hat{j} - 3\hat{k}
p
β
=
4
i
^
+
j
^
β
β
3
k
^
,
q
β
=
β
5
i
^
+
2
j
^
+
3
k
^
\overrightarrow{q} = -5\hat{i} + 2\hat{j} + 3\hat{k}
q
β
=
β
5
i
^
+
2
j
^
β
+
3
k
^
, and
r
β
=
β
5
i
^
+
3
j
^
+
2
k
^
\overrightarrow{r} = -5\hat{i} + 3\hat{j} + 2\hat{k}
r
=
β
5
i
^
+
3
j
^
β
+
2
k
^
. Then
Ξ±
+
2
Ξ²
+
5
Ξ³
\alpha + 2\beta + 5\gamma
Ξ±
+
2
Ξ²
+
5
Ξ³
is equal to:
JEE Main - 2025
Mathematics
Relations and functions
View Solution
Let the range of the function
f
(
x
)
=
6
+
16
cos
β‘
x
β
cos
β‘
(
Ο
3
β
x
)
β
cos
β‘
(
Ο
3
+
x
)
β
sin
β‘
3
x
β
cos
β‘
6
x
,
x
β
R
be
[
Ξ±
,
Ξ²
]
.
f(x) = 6 + 16 \cos x \cdot \cos\left(\frac{\pi}{3} - x\right) \cdot \cos\left(\frac{\pi}{3} + x\right) \cdot \sin 3x \cdot \cos 6x, \quad x \in R \text{ be } [\alpha, \beta].
f
(
x
)
=
6
+
16
cos
x
β
cos
(
3
Ο
β
β
x
)
β
cos
(
3
Ο
β
+
x
)
β
sin
3
x
β
cos
6
x
,
x
β
R
be
[
Ξ±
,
Ξ²
]
.
Then the distance of the point
(
Ξ±
,
Ξ²
)
(\alpha, \beta)
(
Ξ±
,
Ξ²
)
from the line
3
x
+
4
y
+
12
=
0
3x + 4y + 12 = 0
3
x
+
4
y
+
12
=
0
is:
JEE Main - 2025
Mathematics
Relations and functions
View Solution
The relation
R
=
{
(
x
,
y
)
:
x
,
y
β
Z
and
x
+
y
is even
}
R = \{(x, y) : x, y \in \mathbb{Z} \text{ and } x + y \text{ is even} \}
R
=
{(
x
,
y
)
:
x
,
y
β
Z
and
x
+
y
is even
}
is:
JEE Main - 2025
Mathematics
Relations and functions
View Solution
Let the position vectors of three vertices of a triangle be
p
β
=
4
i
^
+
j
^
β
3
k
^
\overrightarrow{p} = 4\hat{i} + \hat{j} - 3\hat{k}
p
β
=
4
i
^
+
j
^
β
β
3
k
^
,
q
β
=
β
5
i
^
+
2
j
^
+
3
k
^
\overrightarrow{q} = -5\hat{i} + 2\hat{j} + 3\hat{k}
q
β
=
β
5
i
^
+
2
j
^
β
+
3
k
^
, and
r
β
=
β
5
i
^
+
3
j
^
+
2
k
^
\overrightarrow{r} = -5\hat{i} + 3\hat{j} + 2\hat{k}
r
=
β
5
i
^
+
3
j
^
β
+
2
k
^
. Then
Ξ±
+
2
Ξ²
+
5
Ξ³
\alpha + 2\beta + 5\gamma
Ξ±
+
2
Ξ²
+
5
Ξ³
is equal to:
JEE Main - 2025
Mathematics
Relations and functions
View Solution
View More Questions
Questions Asked in JEE Advanced exam
Let
S
=
{
(
x
,
y
)
β
R
Γ
R
:
x
β₯
0
,
y
β₯
0
,
y
2
β€
12
β
2
x
and
3
y
+
8
x
β€
5
8
}
S=\left\{(x,y)\in\R\times\R:x\ge0,y\ge0,y^2\le12-2x\ \text{and}\ 3y+\sqrt8\ x\le5\sqrt8\right\}
S
=
{
(
x
,
y
)
β
R
Γ
R
:
x
β₯
0
,
y
β₯
0
,
y
2
β€
12
β
2
x
and
3
y
+
8
β
x
β€
5
8
β
}
. If the area of the region S is
Ξ±
2
\alpha\sqrt2
Ξ±
2
β
, then Ξ± is equal to
JEE Advanced - 2024
Coordinate Geometry
View Solution
Let
S
=
{
(
0
1
c
1
a
d
1
b
e
)
:
a
,
b
,
c
,
d
,
e
β
{
0
,
1
}
and
β£
A
β£
β
{
β
1
,
1
}
}
S=\left\{\begin{pmatrix} 0 & 1 & c \\ 1 & a & d\\ 1 & b & e \end{pmatrix}:a,b,c,d,e\in\left\{0,1\right\}\ \text{and} |A|\in \left\{-1,1\right\}\right\}
S
=
β©
β¨
β§
β
β
0
1
1
β
1
a
b
β
c
d
e
β
β
:
a
,
b
,
c
,
d
,
e
β
{
0
,
1
}
and
β£
A
β£
β
{
β
1
,
1
}
β
β¬
β«
β
, where |A| denotes the determinant of A. Then the number of elements in S is _______.
JEE Advanced - 2024
Matrices
View Solution
A positive, singly ionized atom of mass number
A
M
A_M
A
M
β
is accelerated from rest by the voltage
192
β
V
192 \, \text{V}
192
V
. Thereafter, it enters a rectangular region of width
w
w
w
with magnetic field
B
β
0
=
0.1
k
^
β
T
\vec{B}_0 = 0.1\hat{k} \, \text{T}
B
0
β
=
0.1
k
^
T
. The ion finally hits a detector at the distance
x
x
x
below its starting trajectory. Which of the following option(s) is(are) correct?
(Given: Mass of neutron/proton =
5
3
Γ
1
0
β
27
β
kg, charge of the electron =
1.6
Γ
1
0
β
19
β
C).
\text{(Given: Mass of neutron/proton = } \frac{5}{3} \times 10^{-27} \, \text{kg, charge of the electron = } 1.6 \times 10^{-19} \, \text{C).}
(Given: Mass of neutron/proton =
3
5
β
Γ
1
0
β
27
kg, charge of the electron =
1.6
Γ
1
0
β
19
C).
JEE Advanced - 2024
Electromagnetic Field (EMF)
View Solution
A thin stiff insulated metal wire is bent into a circular loop with its two ends extending tangentially from the same point of the loop. The wire loop has mass
m
m
m
and radius
r
r
r
and is in a uniform vertical magnetic field
B
0
B_0
B
0
β
. When a current
I
I
I
is passed through the loop, the loop turns about the line PQ by an angle
ΞΈ
\theta
ΞΈ
. The angle
ΞΈ
\theta
ΞΈ
is given by:
JEE Advanced - 2024
Electromagnetic Field (EMF)
View Solution
A region in the form of an equilateral triangle (in x-y plane) of height
L
L
L
has a uniform magnetic field
B
\mathbf{B}
B
pointing in the
+
z
+z
+
z
-direction. A conducting loop PQR, in the form of an equilateral triangle of the same height
L
L
L
, is placed in the x-y plane with its vertex
P
P
P
at
x
=
0
x = 0
x
=
0
in the orientation shown in the figure. At
t
=
0
t = 0
t
=
0
, the loop starts entering the region of the magnetic field with a uniform velocity
v
\mathbf{v}
v
along the
+
x
+x
+
x
-direction. The plane of the loop and its orientation remain unchanged throughout its motion.
Which of the following graphs best depicts the variation of the induced emf (
E
\mathcal{E}
E
) in the loop as a function of the distance (
x
x
x
) starting from
x
=
0
x = 0
x
=
0
?
JEE Advanced - 2024
Radioactivity
View Solution
View More Questions