Let S be the sample space of all five digit numbers. It p is the probability that a randomly selected number from S, is multiple of 7 but not divisible by 5, then 9p is equal to
The correct answer is (C):
Among the 5 digit numbers,
First number divisible by 7 is 10003 and last is 99995.
⇒ Number of numbers divisible by 7.
= \(\frac{99995-10003}{7} + 1\)
= 12875
First number divisible by 35 is 10010 and last is 99995.
⇒ Number of numbers divisible by 35 =\(\frac{ 99995-10010}{35}+1 = 2572\)
Hence number of number divisible by 7 but not by 5
= 12857 – 2572
= 10285
9P =\( \frac{10285}{90000} × 9\)
= 1.0285
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