To solve the given problem, we need to determine the equivalence class of the point \((1, -1)\) using the relation \(R =\{( P , Q ) | P\) and \(Q\) are at the same distance from the origin \(\}\).
\(d = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2}\)
\(\sqrt{x^2 + y^2} = \sqrt{2}\)
\(x^2 + y^2 = 2\)
\(S = \{(x, y) \mid x^2 + y^2 = 2\}\)
Therefore, the equivalence class of the point \((1, -1)\) is the set of points \((x, y)\) such that \(x^2 + y^2 = 2\). This corresponds to the correct answer:
\(S = \{(x, y) \mid x^2 + y^2 = 2\}\)
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.
A relation in mathematics defines the relationship between two different sets of information. If two sets are considered, the relation between them will be established if there is a connection between the elements of two or more non-empty sets. Therefore, we can say, ‘A set of ordered pairs is defined as a relation.’
Read Also: Relation and Function
There are 8 main types of relations which are:
There are two ways by which a relation can be represented-
The roster form and set-builder for for a set integers lying between -2 and 3 will be-
I= {-1,0,1,2}
I= {x:x∈I,-2<x<3}