Step 1: Recognize the structure of the matrix \( P \). The matrix \( P \) is a \( 5 \times 5 \) matrix where each off-diagonal element is \( -1 \), and diagonal elements are \( 0 \). This matrix represents the Laplacian matrix of the complete graph \( K_5 \), where each node is connected to every other node. The Laplacian matrix for a complete graph \( K_n \) has the following properties:
One eigenvalue is \( n - 1 \), where \( n \) is the number of vertices (in this case, \( n = 5 \), so one eigenvalue is 4).
The remaining eigenvalues are \( -1 \), with multiplicity \( n - 1 \). Thus, the eigenvalues of \( P \) are: \[ \lambda_1 = 4, \quad \lambda_2 = \lambda_3 = \lambda_4 = \lambda_5 = -1. \] Step 2: Compute the product of the eigenvalues.
The product of the eigenvalues is: \[ \prod_{i=1}^{5} \lambda_i = 4 \times (-1)^4 = 4 \times 1 = 4. \] However, there is a critical point we missed earlier: The matrix \( P \) as it is given actually represents a signed Laplacian matrix for a graph with negative weights. This would imply that the eigenvalues are not simply \( 4 \) and \( -1 \). In fact, the product of eigenvalues will be \( 0 \) because one eigenvalue will be \( 0 \), as this is a property of signed Laplacians where there is always at least one eigenvalue equal to \( 0 \) due to the row-sum property of Laplacian matrices.
Step 3: Correct the product of eigenvalues.
Since one of the eigenvalues is \( 0 \), the product of the eigenvalues is: \[ \prod_{i=1}^{5} \lambda_i = 0. \] Thus, the correct answer is \( \boxed{0} \).