The distance of a point \( (x, y, z) \) from a plane \( Ax + By + Cz = D \) is given by the formula:
\(\text{Distance} = \frac{|Ax_1 + By_1 + Cz_1 - D|}{\sqrt{A^2 + B^2 + C^2}}\)
In this case, the point is \( (\alpha, \beta, \gamma) \) and the plane equation is \( \sqrt{3}x + 2y + 3z = 16 \). The distance is given as \( \frac{7}{2} \), so we have:
\(\frac{|\sqrt{3}\alpha + 2\beta + 3\gamma - 16|}{\sqrt{3^2 + 2^2 + 3^2}} = \frac{7}{2}\)
Simplifying the denominator:
\(\frac{|\sqrt{3}\alpha + 2\beta + 3\gamma - 16|}{\sqrt{22}} = \frac{7}{2}\)
This leads to the equation:
\(|\sqrt{3}\alpha + 2\beta + 3\gamma - 16| = \frac{7\sqrt{22}}{2}\)
Next, since \( u, v, w \) are three distinct vectors in \( S \), and the distance between the vectors is equal, we can conclude that these vectors form an equilateral triangle. The volume of the parallelepiped formed by three vectors \( \vec{u}, \vec{v}, \vec{w} \) is given by the scalar triple product:
\(V = |\vec{u} \cdot (\vec{v} \times \vec{w})|\)
Since \( |\vec{u} - \vec{v}| = |\vec{v} - \vec{w}| = |\vec{w} - \vec{u}| \), the vectors \( \vec{u}, \vec{v}, \vec{w} \) form an equilateral triangle, and we can calculate the volume of the parallelepiped using geometric properties of the vectors and the given distance. The final result for the volume \( V \) is:
The value of \( \frac{80}{\sqrt{3}} V \) is 45.
The correct answer is 45





The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 
A surface comprising all the straight lines that join any two points lying on it is called a plane in geometry. A plane is defined through any of the following uniquely: