Let \( m = 6a \) and \( n = 6b \), where \( a \) and \( b \) are co-prime numbers.
We are given that \( m \) and \( n \) are two-digit numbers.
Thus: \[ 10 \leq m \leq 99 \quad \text{and} \quad 10 \leq n \leq 99 \] So: \[ 10 \leq 6a \leq 99 \quad \Rightarrow \quad 2 \leq a \leq 16 \] and \[ 10 \leq 6b \leq 99 \quad \Rightarrow \quad 2 \leq b \leq 16 \]
Thus, \( a \) and \( b \) are integers, and the pairs \( (a, b) \) where \( \gcd(a, b) = 1 \) and \( a<b \) are the valid solutions.
Now, consider the valid values of \( a \) and \( b \), where both are between 2 and 16 and co-prime.
The valid pairs are as follows:
- \( a = 2, b = 3, 5, 7, 9, 11, 13, 15 \)
- \( a = 3, b = 4, 5, 7, 8, 10, 11, 13, 14, 16 \)
- \( a = 4, b = 5, 7, 9, 11, 13, 14, 16 \)
- \( a = 5, b = 6, 7, 8, 9, 11, 13, 14, 15 \)
- \( a = 6, b = 7, 9, 11, 13, 15 \)
- \( a = 7, b = 8, 9, 10, 11, 13, 14, 16 \)
- \( a = 8, b = 9, 11, 13, 15 \)
- \( a = 9, b = 10, 11, 13, 14, 16 \)
- \( a = 10, b = 11, 13, 15 \)
- \( a = 11, b = 12, 13, 14, 15 \)
- \( a = 12, b = 13, 14, 15, 16 \)
- \( a = 13, b = 14, 15, 16 \)
- \( a = 14, b = 15, 16 \)
- \( a = 15, b = 16 \)
Thus, there are 64 such ordered pairs.
Therefore, the correct answer is \( 64 \).
Step 1: Let \( m = 6a \) and \( n = 6b \), where \( a \) and \( b \) are co-prime numbers.
Step 2: We are given that:
\[ m < n \quad \Rightarrow \quad a < b \]
Step 3: Since \( m \) and \( n \) are two-digit numbers, we have:
\[ 10 \leq m \leq 99 \quad \text{and} \quad 10 \leq n \leq 99 \] This implies: \[ 2 \leq a \leq 16 \quad \text{and} \quad 2 \leq b \leq 16 \]
Step 4: Now, since \( a < b \) and \( a \) and \( b \) are co-prime, we consider the following pairs of \( a \) and \( b \) that satisfy these conditions:
For \( a = 2 \), \( b = 3, 5, 7, 9, 11, 13, 15 \)
For \( a = 3 \), \( b = 4, 5, 7, 8, 10, 11, 13, 14, 16 \)
For \( a = 4 \), \( b = 5, 7, 9, 11, 13, 15 \)
For \( a = 5 \), \( b = 6, 7, 8, 9, 11, 12, 13, 15, 16 \)
For \( a = 6 \), \( b = 7, 11, 13 \)
For \( a = 7 \), \( b = 8, 9, 10, 11, 12, 13, 15, 16 \)
For \( a = 8 \), \( b = 9, 11, 13, 15 \)
For \( a = 9 \), \( b = 10, 11, 13, 14, 16 \)
For \( a = 10 \), \( b = 11, 13, 14, 16 \)
For \( a = 11 \), \( b = 12, 13, 14, 15, 16 \)
For \( a = 12 \), \( b = 13, 14, 15, 16 \)
For \( a = 13 \), \( b = 14, 15, 16 \)
For \( a = 14 \), \( b = 15, 16 \)
For \( a = 15 \), \( b = 16 \)
Step 5: Total number of ordered pairs is \( 64 \).

Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
