Step 1: Use the given decomposition
\[
\frac{H(x)}{(x-1)(x+1)(x-2)} = f(x) + \frac{g(x)}{(x-1)(x+1)(x-2)}
\]
Step 2: Multiply both sides by denominator
\[
H(x) = f(x)(x-1)(x+1)(x-2) + g(x)
\]
Step 3: Evaluate at \(x = -1, 2, 1\)
At \(x=-1\):
\[
H(-1) = g(-1)
\]
At \(x=2\):
\[
H(2) = g(2)
\]
At \(x=1\):
\[
H(1) = g(1)
\]
Step 4: Compute
\[
H(-1) + 2H(2) - 3H(1) = g(-1) + 2g(2) - 3g(1)
\]