Question:

Let for $x \in R$ $f(x)=\frac{x+|x|}{2} \text { and } g(x)=\begin{cases}x, & x<0 \\x^2, & x \geq 0\end{cases} $ 

Then area bounded by the curve $y=(f \circ g)(x)$ and the lines $y=0,2 y-x=15$ is equal to

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When solving for the area under a curve, express the given equation in terms of the function and limits, then calculate the definite integral. If you encounter absolute value functions, split the function into cases based on the sign of the variable.
Updated On: Mar 21, 2025
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Correct Answer: 72

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The correct answer is 72.

2y−x=15 
A=0∫3​(2x+15​−x2)dx+21​×215​×15 
4x2​+215x​−3x3​∣∣​03​+4225​ 
=49​+245​−9+4225​=499−36+225​ 
=4288​=72

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Concepts Used:

Relations and functions

A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.

A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.

Representation of Relation and Function

Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.

  1. Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
  2. Roster form - {(1, 1), (2, 4), (3, 9)}
  3. Arrow Representation