Step 1. Given \( f(x) = x^3 + x^2 f'(1) + x f''(2) + f'''(3) \). Substitute \( f'(1) = -5 \), \( f''(2) = 2 \), \( f'''(3) = 6 \).
Step 2. Calculate \( f'(x) \):
\( f'(x) = 3x^2 + 2x f'(1) + f''(2) \)
Step 3. Evaluate \( f'(10) \):
\( f'(10) = 202 \)
\[ \lim_{x \to -\frac{3}{2}} \frac{(4x^2 - 6x)(4x^2 + 6x + 9)}{\sqrt{2x - \sqrt{3}}} \]
\[ f(x) = \begin{cases} \frac{(4^x - 1)^4 \cot(x \log 4)}{\sin(x \log 4) \log(1 + x^2 \log 4)}, & \text{if } x \neq 0 \\ k, & \text{if } x = 0 \end{cases} \]
Find \( e^k \) if \( f(x) \) is continuous at \( x = 0 \).