Let \( f(x) = (x^3 + 2)^{30} \). If \( f^{(n)}(x) \) is a polynomial of degree \( 20 \), where \( f^{(n)}(x) \) denotes the \( n + h \)-order derivative of \( f(x) \), then the value of \( n \) is:
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For polynomials, the degree of the \( n \)-th derivative decreases by \( n \) for each differentiation.
The degree of the derivative \( f^{(n)}(x) \) is calculated by differentiating the function \( (x^3 + 2)^{30} \). Since the original function has a degree of 90, the degree of the derivative of order \( n \) will be \( 70 \). Hence \( n = 70 \).