Step 1: Analyzing the limits.
First, consider the left-hand limit \( L \) as \( x \to 0^- \). We have the term \( |x| \), which behaves differently for negative \( x \), leading to the non-existence of the limit. For the right-hand limit \( R \), we have the term \( \sin \left( \frac{1}{x} \right) \), which oscillates but remains bounded as \( x \to 0^+ \).
Step 2: Conclusion.
Since the left-hand limit \( L \) exists, but the right-hand limit \( R \) does not exist, the correct answer is (A).