Question:

Let \( f_i: \mathbb{R} \to \mathbb{R} \) for \( i = 1, 2 \) be defined as follows:
\[f_1(x) = \begin{cases} \sin\left(\frac{1}{x}\right) + \cos\left(\frac{1}{x}\right), & \text{if } x \neq 0 \\0, & \text{if } x = 0 \end{cases}\]
and
\[f_2(x) = \begin{cases} x\left(\sin\left(\frac{1}{x}\right) + \cos\left(\frac{1}{x}\right)\right), & \text{if } x \neq 0 \\0, & \text{if } x = 0 \end{cases}\]
Then, determine the continuity of these functions at \( x = 0 \):

Updated On: Oct 1, 2024
  • \( f_1 \) is continuous at \( 0 \) but \( f_2 \) is not continuous at \( 0 \)
  • \( f_1 \) is not continuous at \( 0 \) but \( f_2 \) is continuous at \( 0 \)
  • Both \( f_1 \) and \( f_2 \) are continuous at \( 0 \)
  • Neither \( f_1 \) nor \( f_2 \) is continuous at \( 0 \)
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The Correct Option is B

Solution and Explanation

The correct option is (B): \( f_1 \) is not continuous at \( 0 \) but \( f_2 \) is continuous at \( 0 \)
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