Step 1: Recall probability laws.
We know:
\[
P(E \cup F) = P(E) + P(F) - P(E \cap F).
\]
Also,
\[
0 \le P(E \cap F) \le \min(P(E), P(F)).
\]
Step 2: Checking each option.
(B) is true because union probability is always greater than or equal to the maximum of individual probabilities.
(C) is true since $P(E \cup F)$ cannot exceed $1$ or $P(E) + P(F)$.
(D) is true since intersection cannot exceed either individual probability.
(A) is not always true because the inequality involving complements does not hold for all probability combinations — it can fail for certain $E$, $F$ with small intersection or independence.
Step 3: Conclusion.
Hence, statement (A) is NOT always true.