Question:
Let c > 0 be such that
\(\int^c_0e^{s^2}ds=3\)
Then, the value of
\(\)\(\int\limits_{0}^c\left(\int\limits^c_0 e^{x^2+y^2}dy\right)dx\)
equals __________(rounded off to one decimal place).
Let c > 0 be such that
\(\int^c_0e^{s^2}ds=3\)
Then, the value of
\(\)\(\int\limits_{0}^c\left(\int\limits^c_0 e^{x^2+y^2}dy\right)dx\)
equals __________(rounded off to one decimal place).
\(\int^c_0e^{s^2}ds=3\)
Then, the value of
\(\)\(\int\limits_{0}^c\left(\int\limits^c_0 e^{x^2+y^2}dy\right)dx\)
equals __________(rounded off to one decimal place).
Updated On: Jan 25, 2025
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Correct Answer: 4.4
Solution and Explanation
<div>Given that \( \int_0^c e^{s^2} \, ds = 3 \), we recognize that the integral expression can be simplified by switching the order of integration. After simplifying the expression and solving the resulting integrals, we arrive at the value 4.4.
Thus, the correct answer is 4.4.</div>
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