Question:

Let 𝑔: ℝ β†’ ℝ be a continuous function. Which one of the following is the solution of the differential equation
\(\frac{d^2y}{dx^2}+y=g(x)\ \ \ \ \text{for}\ x \in \R\),
satisfying the conditions y(0) = 0, y'(0) = 1 ?

Updated On: Aug 13, 2024
  • \(y(x)=\sin x-\int^x_0 \sin(x-t)g(t)dt\)
  • \(y(x)=\sin x+\int^x_0 \sin(x-t)g(t)dt\)
  • \(y(x)=\sin x-\int^x_0 \cos(x-t)g(t)dt\)
  • \(y(x)=\sin x+\int^x_0 \cos(x-t)g(t)dt\)
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The Correct Option is B

Solution and Explanation

The correct option is (B) : \(y(x)=\sin x+\int^x_0 \sin(x-t)g(t)dt\).
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