To solve the differential equation \(\frac{d^2y}{dx^2}+y=g(x)\) with the initial conditions \(\(y(0) = 0\)\) and \(\(y'(0) = 1\)\), we use the theory of linear differential equations and Green's functions.
The given differential equation is non-homogeneous. For such equations, we find the general solution as a sum of the complementary function (solution of the homogeneous equation) and a particular solution.
\(\frac{d^2y}{dx^2} + y = 0\).
Its characteristic equation is \(r^2 + 1 = 0\), giving roots \(r = \pm i\).
The complementary function is:
\(y_c(x) = C_1 \cos x + C_2 \sin x\).
To find the particular solution using the method of undetermined coefficients or the variation of parameters, assume a particular solution as:
\(\int^x_0 \sin(x-t)g(t)dt\).
The general solution is:
\(y(x) = C_1 \cos x + C_2 \sin x + \int^x_0 \sin(x-t)g(t)dt\).
Apply initial conditions \(y(0) = 0\) and \(y'(0) = 1\):
\(C_1 \cdot 1 + C_2 \cdot 0 = 0\) β \(C_1 = 0\)
First, find \(y'(x)\):
\(y'(x) = C_1 (-\sin x) + C_2 (\cos x) + \frac{d}{dx} \left( \int^x_0 \sin(x-t)g(t)dt \right)\)
\(= C_2 \cos x + \sin(x-t) g(t) \; |_{t=0}^{t=x}\)
Evaluate at \(x = 0\):
\(y'(0) = C_2 \cdot 1 + 0 = 1\) β \(C_2 = 1\)
\(y(x) = \sin x + \int^x_0 \sin(x-t)g(t)dt\)
Thus, the correct option is:
\(y(x) = \sin x + \int^x_0 \sin(x-t)g(t)dt\)
This option aligns with the initial conditions and the form required to solve the given differential equation using standard methods for non-homogeneous linear differential equations with constant coefficients.
Let \( f : [1, \infty) \to [2, \infty) \) be a differentiable function. If
\( 10 \int_{1}^{x} f(t) \, dt = 5x f(x) - x^5 - 9 \) for all \( x \ge 1 \), then the value of \( f(3) \) is ______.