Let A1, A2, A3, A4,........, A8 be the vertices of the regular octagons that lie on the circle of radius 2. Let p be a point on the circle and let PAi denote the distance between the point P and Ai for i = 1,2,3,....,8. If P varies over the circle, then the maximum value of the product is PA1.PA2..........PA8, is
According to the question, Ai are 8th root of 28 & let P be 2eiα.
Now, z8 – 28 = (z – A1) (z – A2) ……… (z – A8)
So, Put z = 2eiα
⇒ 28ei8α – 28 = (2eiα – A1) (2eiα – A2) (2eiα – A3) ….. (2eiα – A8)
⇒ 28 |ei8α – 1| = |(2eiα – A1) (2eiα – A2) (2eiα – A3) ….. (2eiα – A8)|
⇒ 28 |ei4α – e–i4α | = |(2eiα – A1) (2eiα – A2) (2eiα – A3) ….. (2eiα – A8)|
⇒ 29 |sin4α| = |(2eiα – A1) (2eiα – A2) (2eiα – A3) ….. (2eiα – A8)|
So, from this we get that :
Maximum value of the PA1.PA2 …… PA8 = 29
Therefore, the correct answer is 29 = 512.
\[ f(x) = \begin{cases} x\left( \frac{\pi}{2} + x \right), & \text{if } x \geq 0 \\ x\left( \frac{\pi}{2} - x \right), & \text{if } x < 0 \end{cases} \]
Then \( f'(-4) \) is equal to:If \( f'(x) = 4x\cos^2(x) \sin\left(\frac{x}{4}\right) \), then \( \lim_{x \to 0} \frac{f(\pi + x) - f(\pi)}{x} \) is equal to:
Let \( f(x) = x \sin(x^4) \). Then \( f'(x) \) at \( x = \sqrt[4]{\pi} \) is equal to:
In mathematics, Geometry is one of the most important topics. The concepts of Geometry are defined with respect to the planes. So, Geometry is divided into three categories based on its dimensions which are one-dimensional geometry, two-dimensional geometry, and three-dimensional geometry.
Let's consider line ‘L’ is passing through the three-dimensional plane. Now, x,y, and z are the axes of the plane, and α,β, and γ are the three angles the line making with these axes. These are called the plane's direction angles. So, correspondingly, we can very well say that cosα, cosβ, and cosγ are the direction cosines of the given line L.
Read More: Introduction to Three-Dimensional Geometry