Question:
Let a second order difference equation be
\(y_{n+2} + 4y_n = 4y_{n+1}, \, n=2,3,4,......, \,\, y_0=1, y_1=4\)
Then the general solution is
Let a second order difference equation be
\(y_{n+2} + 4y_n = 4y_{n+1}, \, n=2,3,4,......, \,\, y_0=1, y_1=4\)
Then the general solution is
\(y_{n+2} + 4y_n = 4y_{n+1}, \, n=2,3,4,......, \,\, y_0=1, y_1=4\)
Then the general solution is
Updated On: Oct 1, 2024
- \((1+n^2)2^n\)
- \((1+n)2^n\)
- \((1+\frac1{n})2^n\)
- \((n^2+n+1)2^n\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \((1+n)2^n\)
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