Question:

Let A and B be two events such that 0 < P(A) < 1 and 0 < P(B) < 1. Then which one of the following statements is NOT true ?

Updated On: Nov 25, 2025
  • If A(A|B) > P(A), then P(B|A) > P(B)
  • If P(A ∪ B) = 1, then A and B cannot be independent
  • If P(A|B) > P(A), then P(Ac|B) < P(Ac)
  • If P(A|B) > P(A), then P(Ac|Bc) < P(Ac)
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The Correct Option is D

Solution and Explanation

To solve the question, we need to analyze each statement using probability principles, particularly the concept of conditional probability and independence. Let's go through each option step by step.

Option Analysis:

  1. \(P(A|B) > P(A) \Rightarrow P(B|A) > P(B)\)
    • This statement uses the relationship between the conditional probabilities and the Bayes' theorem. If \(P(A|B) > P(A)\), it indicates that event A is more likely given B has occurred, thereby increasing the likelihood of B given A. Hence, \(P(B|A) > P(B)\).
  2. \(P(A \cup B) = 1 \Rightarrow \text{A and B cannot be independent}\)
    • When \(P(A \cup B) = 1\), it implies that one of the events A or B must occur. For independent events, \(P(A \cup B) = P(A) + P(B) - P(A)P(B)\), but if they were independent, \(P(A)P(B) \neq 0\) and the probability would not sum to 1 unless some dependency exists. Hence, this statement is true.
  3. \(P(A|B) > P(A) \Rightarrow P(A^c|B) < P(A^c)\)
    • If \(P(A|B) > P(A)\), then A is more likely to happen given B. Correspondingly, it decreases the likelihood of the complement of A under the same condition B, resulting in \(P(A^c|B) < P(A^c)\). Hence, this statement is true.
  4. \(P(A|B) > P(A) \Rightarrow P(A^c|B^c) < P(A^c)\)
    • This statement is not necessarily true. \(P(A^c|B^c)\) concerns the probability of the complement of A given that B has not occurred. The occurrence likelihood of \(A^c\) given \(B^c\) does not directly follow from an increase in \(P(A|B) > P(A)\). Hence, this is the incorrect statement among the options.

Conclusion:

The statement that is NOT true is: \(P(A|B) > P(A) \Rightarrow P(A^c|B^c) < P(A^c)\). This statement incorrectly relates the conditional probabilities without direct correlation.

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