Let \(\vec a\) anb \(\vec b\) be two unit vectors and θ is the angle between them.Then,\(\vec a+\vec b\) is a unit vector if
θ=\(\frac{\pi}{4}\)
θ=\(\frac{\pi}{3}\)
θ=\(\frac{\pi}{2}\)
θ=\(\frac{2\pi}{3}\)
Let a→and b→be two unit vectors and θ be the angle between them.
Then,|\(\vec a\)|=|\(\vec b\)|=1
Now,\(\vec a\)+\(\vec b\) is a unit vector if |\(\vec a+\vec b\)|=1.
|\(\vec a+\vec b\)|=1
⇒(\(\vec a+\vec b\))2=1
⇒(\(\vec a+\vec b\)).(\(\vec a+\vec b\))=1
⇒\(\vec a.\vec a+\vec b.\vec b\)+\(\vec b.\vec a+\vec b.\vec b\)=1
⇒|\(|\vec a|^2+2\vec a.\vec b+|\vec b|^2\)=1
⇒1+2.1.1cosθ+1=1
⇒cosθ=\(-\frac{1}{2}\)
⇒ θ=\(\frac{2\pi}{3}\)
Hence,\(\vec a+\vec b\) is a unit vector if θ=\(\frac{2\pi}{3}\)
The correct answer is D.
If \( X \) is a random variable such that \( P(X = -2) = P(X = -1) = P(X = 2) = P(X = 1) = \frac{1}{6} \), and \( P(X = 0) = \frac{1}{3} \), then the mean of \( X \) is
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.
A vector is an object which has both magnitudes and direction. It is usually represented by an arrow which shows the direction(→) and its length shows the magnitude. The arrow which indicates the vector has an arrowhead and its opposite end is the tail. It is denoted as
The magnitude of the vector is represented as |V|. Two vectors are said to be equal if they have equal magnitudes and equal direction.
Arithmetic operations such as addition, subtraction, multiplication on vectors. However, in the case of multiplication, vectors have two terminologies, such as dot product and cross product.