1. (i) All elements of $R$:
We need to find all pairs $(x, y)$ such that $x + y = 6$ with $x \in A = \{1, 2, 3\}$ and $y \in B = \{4, 5, 6\}$.
- For $x = 1$, we have $y = 6 - 1 = 5$. So, the pair is $(1, 5)$.
- For $x = 2$, we have $y = 6 - 2 = 4$. So, the pair is $(2, 4)$.
- For $x = 3$, we have $y = 6 - 3 = 3$, but since $3 \notin B$, no pair is formed for $x = 3$.
Therefore, the relation $R$ is
\[ R = \{(1, 5), (2, 4)\}. \]
2. (ii) Is $R$ a function? Justify.
A relation is a function if every element of the domain is associated with exactly one element of the codomain.
- Here, $x = 1$ is associated with $y = 5$ and $x = 2$ is associated with $y = 4$.
- No element in $A$ is associated with more than one element in $B$.
Therefore, $R$ is a function.
3. (iii) Domain and Range of $R$:
- The domain of $R$ is the set of all $x$ values in $A$ for which there is a corresponding $y$ in $B$. In this case, the domain is
\[ \text{Domain}(R) = \{1, 2\}. \]
- The range of $R$ is the set of all $y$ values in $B$ that are associated with some $x$ in $A$. In this case, the range is
\[ \text{Range}(R) = \{4, 5\}. \]