Given :
f(1) = f(1 x 1) = f(1) x f(1) ⇒ f(1) = 1
f(9) = f(3x 3) = f(3) x f(3) ⇒f(3) = 1, f(9) = 1 or f(3) = 3, f(9) = 9
If f(1) = 1, f(3) = 1, f(9) = 1
Then f(2), f(5), f(8) each mapped in 6 ways
∴ Number of ways = 63 = 216
∴ Number of ways = 63 = 216
Total Ways = 216 + 216 = 432
So, the correct answer is 432.
Let \(S ={ (\begin{matrix} -1 & 0 \\ a & b \end{matrix}), a,b, ∈(1,2,3,.....100)}\) and
let \(T_n = {A ∈ S : A^{n(n + 1)} = I}. \)
Then the number of elements in \(\bigcap_{n=1}^{100}\) \(T_n \) is
Cartesian products of sets here are explained with the help of an example. Consider A and B to be the 2 sets such that A is a set of 3 colors of tables and B is a set of 3 colors of chairs objects, i.e.,
A = {red, blue, purple}
B = {brown, green, yellow},
Now let us find the number of pairs of colored objects that we can make from a set of tables and chairs in various combinations. They can be grouped as given below:
(red, brown), (red, green), (red, yellow), (blue, brown), (blue, green), (blue, yellow), (purple, brown), (purple, green), (purple, yellow)
There are 9 such pairs in the Cartesian product since 3 elements are there in each of the defined sets A and B. The above-ordered pairs shows the definition for the Cartesian product of sets given. This product is resembled by “A × B”.