Given \( A = \{1, 2, 3, 4\} \) and \( R = \{(1, 2), (2, 3), (1, 4)\} \), for \( R \) to be an equivalence relation, it must satisfy the following properties: reflexive, symmetric, and transitive.
Reflexivity: Add all pairs of the form \((a, a)\), where \( a \in A \):
\(\{(1, 1), (2, 2), (3, 3), (4, 4)\}\)
Symmetry: Add pairs such that if \((a, b) \in R\), then \((b, a)\) must also belong to \( R \):
\(\{(2, 1), (3, 2), (4, 1)\}\)
Transitivity: Ensure that if \((a, b) \in R\) and \((b, c) \in R\), then \((a, c) \in R\). For example:
\((1, 2), (2, 3) \implies (1, 3)\)
Applying this to all pairs results in:
\(\{(1, 3), (3, 1), (2, 4), (4, 2), (4, 3), (3, 4)\}\)
Combining all the above, the final relation \( R \) becomes:
\(R = \{(1, 1), (2, 2), (3, 3), (4, 4), (1, 2), (2, 1), (2, 3), (3, 2), (1, 4), (4, 1), (1, 3), (3, 1), (2, 4), (4, 2), (4, 3), (3, 4)\}\)
Thus, the total number of elements in \( R \) is 16.
\(\boxed{\text{Answer: } 16.}\)
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: