Question

Let 𝐸₁, 𝐸₂ and 𝐸₃ be three events such that 𝑃(𝐸₁∩𝐸₂ )=\(\frac{1}{4}\) , 𝑃(𝐸₁ ∩ 𝐸₃ )=𝑃(𝐸₂ ∩ 𝐸₃ )=\(\frac{1}{5}\) and 𝑃(𝐸₁ ∩ 𝐸₂ ∩ 𝐸₃ ) =\(\frac{1}{6}\) . Then, among the events 𝐸₁ 𝐸₂ and 𝐸₃, the probability that at least two events occur, equals

• A. \(\frac{17}{60}\)
• B. \(\frac{23}{60}\)
• C. \(\frac{19}{60}\)
• D. \(\frac{29}{60}\)

Answer 1

The Correct Option is C

The correct option is (C): \(\frac{19}{60}\)