Question:
Let π1~π(2, 1), π2~π(β1,4) and π3~π(0, 1) be mutually independent random variables. Then, the probability that exactly two of these three random variables are less than 1, equals____(round off to two decimal places)
Let π1~π(2, 1), π2~π(β1,4) and π3~π(0, 1) be mutually independent random variables. Then, the probability that exactly two of these three random variables are less than 1, equals____(round off to two decimal places)
Updated On: Oct 1, 2024
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Correct Answer: 0.63
Solution and Explanation
The correct answer is: 0.63 to 0.65 (approx)
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