Question:

Lanthanoid ions with \(4f^7\) configuration are: (A) Eu\(^{2+}\) (B) Gd\(^{3+}\) (C) Eu\(^{3+}\) (D) Tb\(^{3+}\) (E) Sm\(^{2+}\) Choose the correct answer from the options given below:

Show Hint

Remember the electronic configurations of lanthanoid ions and how to determine the number of 4f electrons.
Updated On: Mar 21, 2025
  • (A) and (B) only
  • (A) and (D) only
  • (B) and (E) only
  • (B) and (C) only
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Write the electronic configurations.


\(_{63}\)Eu\(^{2+}\) - [Xe] 4f\(^7\) 6s\(^0\)
\(_{64}\)Gd\(^{3+}\) - [Xe] 4f\(^7\) 5d\(^0\) 6s\(^0\)
\(_{63}\)Eu\(^{3+}\) - [Xe] 4f\(^6\) 6s\(^0\)
\(_{65}\)Tb\(^{3+}\) - [Xe] 4f\(^8\) 6s\(^0\)
\(_{62}\)Sm\(^{2+}\) - [Xe] 4f\(^6\) 6s\(^0\)


Step 2: Identify the ions with 4f\(^7\) configuration.


From the electronic configurations, we can see that Eu\(^{2+}\) and Gd\(^{3+}\) have 4f\(^7\) configurations.


Step 3: Select the correct option.


Therefore, the correct answer is (A) and (B) only.

Was this answer helpful?
0
0