Question

It is because of inability of ns² electrons of the valence shell to participate in bonding that

• A. \(Sn^{2+}\) is reducing while \( Pb^{4+}\) is oxidising
• B. \(Sn^{2+}\) is oxidising while \(Pb^{4+}\) is reducing
• C. \(Sn^{2+}\) and \(Pb^{2+}\) are both oxidising and reducing
• D. \(Sn^{4+}\) is reducing while \(Pb^{4+}\) is oxidising

Answer 1

The Correct Option is A

The correct option is (\(Sn^{2+}\) is reducing while \( Pb^{4+}\) is oxidising): .