When HCl is used in the presence of KMnO\(_4\), KMnO\(_4\) (potassium permanganate) acts as a strong oxidizing agent. KMnO\(_4\) oxidizes chloride ions (Cl\(^-\)) from HCl to chlorine gas (Cl\(_2\)):
\[
\text{2 Cl}^- + \text{2 H}^+ → \text{Cl}_2(g) + \text{H}_2\text{O}
\]
Since Cl\(_2\) is also a strong oxidizing agent, this reaction competes with the oxidation of KMnO\(_4\), preventing HCl from acting as an acidic medium. Thus, HCl is not suitable for making the medium acidic in oxidation reactions of KMnO\(_4\).
Final Answer:
\[
\boxed{\text{The correct answer is (2), KMnO}_4\text{ oxidizes HCl into Cl}_2\text{, which is also an oxidizing agent.}}
\]