Question:

The reagent(s) used in hydroboration oxidation of propene are:
(A) B\(_2\)H\(_6\)
(B) H\(_2\)O
(C) H\(_2\)O\(_2\)
(D) OH\(^-\)

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Hydroboration-oxidation is a useful reaction for the anti-Markovnikov addition of water to alkenes. The reaction proceeds with syn addition to form an alcohol.
Updated On: Sep 9, 2025
  • (A), (B) and (D) only
  • (A), (B) and (C) only
  • (A), (B), (C) and (D)
  • (B), (C) and (D) only
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The Correct Option is B

Solution and Explanation

Step 1: Understanding Hydroboration Oxidation.
Hydroboration-oxidation of alkenes is a two-step reaction. In the first step, the alkene reacts with diborane (B\(_2\)H\(_6\)), and in the second step, oxidation occurs using hydrogen peroxide (H\(_2\)O\(_2\)) to yield alcohols.
Step 2: Reagents Used.
- (A) B\(_2\)H\(_6\) (diborane): This is the key reagent used in the hydroboration step. It reacts with the alkene to form an organoborane intermediate.
- (B) H\(_2\)O (water): Water is essential in the oxidation step, where it reacts with the intermediate to form an alcohol.
- (C) H\(_2\)O\(_2\) (hydrogen peroxide): Hydrogen peroxide is used for the oxidation step to convert the organoborane intermediate into an alcohol.
- (D) OH\(^-\) (hydroxide ion): The hydroxide ion is not involved in the reaction.
Step 3: Conclusion.
The correct reagents used in the hydroboration oxidation of propene are B\(_2\)H\(_6\), H\(_2\)O, and H\(_2\)O\(_2\). Hence, the correct answer is:
(2) (A), (B) and (C) only.
Final Answer: \[ \boxed{\text{The correct answer is (A), (B) and (C) only.}} \]
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