We are given the integral:
\[
I = \int \frac{dx}{x \log x}
\]
This is a standard integral, which can be solved using the substitution method. Let:
\[
u = \log x \quad \text{so that} \quad du = \frac{dx}{x}
\]
Substituting this into the integral:
\[
I = \int \frac{du}{u} = \log u + k = \log (\log x) + k
\]
Thus, the correct answer is \( \log(\log x) + k \).