Question:
\( \int \frac{\cos 2x}{\sin^2 x \cos^2 x} \, dx \) is equal to:
\( \int \frac{\cos 2x}{\sin^2 x \cos^2 x} \, dx \) is equal to:
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Use trigonometric identities and substitution to break down complex integrals. Simplify before solving!
Updated On: Jan 13, 2026
- \( \cot x + \tan x + C \)
- \( - (\cot x + \tan x) + C \)
- \( - \cot x + \tan x + C \)
- \( \cot x - \tan x + C \)
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The Correct Option is A
Solution and Explanation
We can simplify the integrand: \[ \frac{\cos 2x}{\sin^2 x \cos^2 x} = \frac{\cos^2 x - \sin^2 x}{\sin^2 x \cos^2 x} \] Use trigonometric identities and substitution to solve. This simplifies to the expression \( \cot x + \tan x + C \).
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