Step 1: Understanding the Concept
This integral can be solved by first simplifying the integrand using trigonometric identities and then recognizing that the resulting expression is the derivative of a product of functions.
Step 2: Key Formula or Approach
1. Use the Pythagorean identity $1+\tan^2 x = \sec^2 x$ to simplify the integrand.
2. Expand the simplified expression.
3. Recognize the expanded form as the result of applying the product rule of differentiation, $\frac{d}{dx}(uv) = u'v+uv'$.
4. Integrate the recognized derivative.
Step 3: Detailed Explanation
The integral is $I = \int(1+\tan^2 x)(1+2x\tan x)dx$.
1. Simplify the integrand:
Using the identity $1+\tan^2 x = \sec^2 x$, the integrand becomes:
\[ \sec^2 x(1+2x\tan x) \]
Expand this expression:
\[ \sec^2 x + 2x\tan x\sec^2 x \]
2. Recognize the derivative form:
The expression looks like the result of a product rule. Let's consider the function $f(x) = x \sec^2 x$. Let's find its derivative using the product rule, where $u=x$ and $v=\sec^2 x$.
\[ f'(x) = \frac{d}{dx}(x) \cdot \sec^2 x + x \cdot \frac{d}{dx}(\sec^2 x) \]
We need the derivative of $\sec^2 x$. Using the chain rule:
\[ \frac{d}{dx}(\sec^2 x) = 2\sec x \cdot \frac{d}{dx}(\sec x) = 2\sec x \cdot (\sec x \tan x) = 2\sec^2 x \tan x \]
Substituting this back into the product rule:
\[ f'(x) = 1 \cdot \sec^2 x + x \cdot (2\sec^2 x \tan x) = \sec^2 x + 2x\sec^2 x \tan x \]
This is exactly the integrand we obtained after simplification.
3. Evaluate the integral:
Since the integrand is the derivative of $x\sec^2 x$, the integral is simply the function itself.
\[ I = \int \frac{d}{dx}(x\sec^2 x) dx = x\sec^2 x + c \]
Step 4: Final Answer
The integral evaluates to $x\sec^2 x + c$.