Question:
$\int^1_0 x \, \tan^{-1} x\,dx = $
$\int^1_0 x \, \tan^{-1} x\,dx = $
Updated On: Jun 23, 2024
- $\frac{\pi}{4} + \frac{1}{2}$
- $\frac{\pi}{4} - \frac{1}{2}$
- $\frac{1}{2} - \frac{\pi}{4} $
- $ - \frac{\pi}{4} - \frac{1}{2}$
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The Correct Option is B
Solution and Explanation
Answer (b) $\frac{\pi}{4} - \frac{1}{2}$
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Concepts Used:
Integrals of Some Particular Functions
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
Integrals of Some Particular Functions:
- ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
- ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
- ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
- ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
- ∫1/√(a2 – x2) dx = sin-1(x/a) + C
- ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C
These are tabulated below along with the meaning of each part.
