
To solve the given problem, we need to analyze the logic circuit and determine the output for the inputs \( A = 0, B = 1 \) and \( A = 1, B = 0 \), which correspond to finding \( X \) and \( Y \) in the truth table. Let's break it down step-by-step:
1. Analyzing the Circuit:
2. Calculating the Output:
Case 1: \( A = 0, B = 1 \) (Find \( X \))
Thus, for \( A = 0, B = 1 \), the output \( X = 1 \).
Case 2: \( A = 1, B = 0 \) (Find \( Y \))
Thus, for \( A = 1, B = 0 \), the output \( Y = 1 \).
Conclusion:
From the analysis, both \( X \) and \( Y \) are 1 for the respective inputs and configurations. Therefore, the correct answer is 1,1.
Let us analyze the given logic circuit and find the values of \( X \) and \( Y \).
The first AND gate has inputs \( A \) and \( B \). The output \( E \) will be:
\[ E = A \cdot B. \]
The second AND gate has inputs \( A \) and \( E \) (output from the first gate). The output \( X \) will be:
\[ X = A \cdot E = A \cdot (A \cdot B) = A^2 \cdot B. \]
The OR gate takes inputs \( A \) and \( B \) and gives the output \( Y \):
\[ Y = A + B. \]
| A | B | E | X | Y | |---|---|---|---|---| | 0 | 0 | 0 | 0 | 0 | | 0 | 1 | 0 | 0 | 1 | | 1 | 0 | 0 | 0 | 1 | | 1 | 1 | 1 | 1 | 1 |
Thus, the values of \( X \) and \( Y \) for \( A = 1 \) and \( B = 1 \) are \( X = 1 \) and \( Y = 1 \). The correct answer is Option (1).



The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
Consider the following logic circuit.
The output is Y = 0 when :