
To solve the given problem, we need to analyze the logic circuit and determine the output for the inputs \( A = 0, B = 1 \) and \( A = 1, B = 0 \), which correspond to finding \( X \) and \( Y \) in the truth table. Let's break it down step-by-step:
1. Analyzing the Circuit:
2. Calculating the Output:
Case 1: \( A = 0, B = 1 \) (Find \( X \))
Thus, for \( A = 0, B = 1 \), the output \( X = 1 \).
Case 2: \( A = 1, B = 0 \) (Find \( Y \))
Thus, for \( A = 1, B = 0 \), the output \( Y = 1 \).
Conclusion:
From the analysis, both \( X \) and \( Y \) are 1 for the respective inputs and configurations. Therefore, the correct answer is 1,1.
Let us analyze the given logic circuit and find the values of \( X \) and \( Y \).
The first AND gate has inputs \( A \) and \( B \). The output \( E \) will be:
\[ E = A \cdot B. \]
The second AND gate has inputs \( A \) and \( E \) (output from the first gate). The output \( X \) will be:
\[ X = A \cdot E = A \cdot (A \cdot B) = A^2 \cdot B. \]
The OR gate takes inputs \( A \) and \( B \) and gives the output \( Y \):
\[ Y = A + B. \]
| A | B | E | X | Y | |---|---|---|---|---| | 0 | 0 | 0 | 0 | 0 | | 0 | 1 | 0 | 0 | 1 | | 1 | 0 | 0 | 0 | 1 | | 1 | 1 | 1 | 1 | 1 |
Thus, the values of \( X \) and \( Y \) for \( A = 1 \) and \( B = 1 \) are \( X = 1 \) and \( Y = 1 \). The correct answer is Option (1).



Which of the following circuits has the same output as that of the given circuit?

Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?

Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.