Question:

In the reaction, A \( \rightarrow \) products, if the concentration of the reactant is doubled but the rate of reaction remains unchanged, what is the order of the reaction with respect to A?

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In a zero-order reaction, the rate is independent of the concentration of reactants.
Updated On: Mar 24, 2025
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Rate Law 
The general rate law is: \[ r = k[A]^n \] where \( n \) is the order of the reaction. 
Step 2: Given Condition 
When the concentration of \( A \) is doubled, the rate remains unchanged. 
Mathematically, \[ r_2 = k[2A]^n \] Since \( r_1 = r_2 \), we equate: \[ k[A]^n = k[2A]^n \] 
Step 3: Solving for \( n \) 
Dividing both sides: \[ 1 = 2^n \] \[ 2^n = 1 \] \[ n = 0 \] Final Answer: The reaction follows zero order kinetics.

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