The overall order of a reaction is determined by summing the exponents of the concentration terms in the rate law.
In this case, the rate law is given as \( \text{Rate} = k[A]^2[B] \).
The exponent of \( [A] \) is 2 and the exponent of \( [B] \) is 1.
Therefore, the overall order is \( 2 + 1 = 3 \).
The decomposition of a compound A follows first-order kinetics. The concentration of A at time t = 0 is 1.0 mol L-1. After 60 minutes, it reduces to 0.25 mol L-1. What is the initial rate of the reaction at t = 0? (Take ln 2 = 0.693)