The atomic number of the central metal atom can be determined by the EAN rule.
Given : metal carbonyl is M(CO)x where, M = metal x = 4
Thus, the metal carbonyl is M(CO)4The CO is a neutral ligand, having a lone pair of electrons.
It is a monodentate ligand.
Thus, electrons donated per ligand per donor atom = 2 Number of electrons donated by 4 CO molecule = 2 × 4 = 8 electrons.
According to the EAN rule, the ligands in the coordination sphere of a transition metal complex must provide the necessary number of electrons that will give the central metal ion the electronic configuration of a noble gas.
We know that,Effective atomic number (EAN) for M = Atomic number of M (Z) + Number of electrons donated by 4COLet EAN be 36 (Atomic number of krypton, a rare gas).
36 = Z + 8Z = 36 - 8 = 28
Therefore,Atomic number of M = 28
Hence, the correct option is (D).
Identify the correct orders against the property mentioned:
A. H$_2$O $>$ NH$_3$ $>$ CHCl$_3$ - dipole moment
B. XeF$_4$ $>$ XeO$_3$ $>$ XeF$_2$ - number of lone pairs on central atom
C. O–H $>$ C–H $>$ N–O - bond length
D. N$_2$>O$_2$>H$_2$ - bond enthalpy
Choose the correct answer from the options given below:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.