Question:

In the given structure, number of \( sp \) and \( sp^2 \) hybridized carbon atoms present respectively are: 

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Carbon atoms involved in triple bonds are \( sp \)-hybridized, while those involved in double bonds (or with a lone pair) are \( sp^2 \)-hybridized.
Updated On: Oct 30, 2025
  • \( 3 \) and \( 5 \)
  • \( 4 \) and \( 5 \)
  • \( 3 \) and \( 6 \)
  • \( 4 \) and \( 6 \)
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The Correct Option is A

Approach Solution - 1

- The structure contains \( sp \) and \( sp^2 \) hybridized carbon atoms.
- The carbon atoms in triple bonds (i.e., the C≡N bond) are \( sp \)-hybridized.
- The carbon atoms in the C=C double bonds and in the C=O group are \( sp^2 \)-hybridized.
- Thus, the number of \( sp \)-hybridized atoms is 3 and the number of \( sp^2 \)-hybridized atoms is 5.

Final Answer: Option (1).
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Approach Solution -2

Step 1: Analyze the given structure.
The given structure consists of various bonds between carbon (C), nitrogen (N), and oxygen (O) atoms. We need to determine the hybridization of the carbon atoms present in the structure.

Step 2: Identify the hybridization of each carbon atom.
- The carbon atoms that are involved in a triple bond (such as the one attached to nitrogen) will have **sp hybridization**. This is because a triple bond consists of one sigma bond and two pi bonds, and the carbon involved in this bond needs to have two unhybridized p-orbitals. Hence, these carbon atoms are **sp hybridized**.
- The carbon atoms involved in double bonds (such as the one attached to oxygen) will have **sp2 hybridization**. This is because a double bond consists of one sigma bond and one pi bond, and the carbon involved in this bond needs to have one unhybridized p-orbital. Hence, these carbon atoms are **sp2 hybridized**.

Step 3: Count the number of sp and sp2 hybridized carbon atoms.
- There are 3 **sp hybridized** carbon atoms (the ones involved in the triple bond with nitrogen).
- There are 5 **sp2 hybridized** carbon atoms (the ones involved in double bonds with oxygen and in the other single bonds).

Final Answer:
\[ \boxed{3 \text{ and } 5} \]
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