Question

In the given reaction sequence, identify Z.

• A.

  

• B.

  

• C.

  

• D.

  

Hint:

Hoffmann bromamide reaction converts amides to amines, and the Sandmeyer reaction can replace a diazonium group with CN, Cl, Br, or OH.

Answer 1

The Correct Option is C

Step 1: Reaction 1 - Conversion of Benzoic Acid to Benzamide - The given compound is benzoic acid \((C_6H_5COOH)\). 
- The first step involves reaction with ammonia \((NH_3)\) to form benzamide \((C_6H_5CONH_2)\). 

Step 2: Reaction 2 - Hoffmann Bromamide Reaction - When benzamide reacts with bromine \((Br_2)\) in NaOH, it undergoes Hoffmann Bromamide rearrangement. 
- This reaction converts the amide group (-CONH\(_2\)) into an amine (-NH\(_2\)), forming aniline \((C_6H_5NH_2)\). 

Step 3: Reaction 3 - Sandmeyer Reaction - The next step is the Sandmeyer reaction. - Aniline is converted to a diazonium salt \((C_6H_5N_2^+Cl^-)\) by treating it with NaNO\(_2\) and HCl. - On treatment with CuCN, the diazonium salt gets converted to benzonitrile \((C_6H_5CN)\). Step 4: Identifying Z - Since the final step involves conversion to a nitrile (-CN) group, the correct answer is benzonitrile (C$_6$H$_5$CN).