
\(1.5 \;sin60° = 4 \;sin90°\)
\(1.5×\frac{\sqrt3}{2}\)
=\(\frac{3\sqrt3}{4}\)
=\(\frac{\sqrt{27}}{4}\)
=\(\frac{x}{4}\)
\(x = 27\)
| List-I | List-II | ||
| P | If \(n = 2\) and \(\alpha = 180°\), then all the possible values of \(\theta_0\) will be | I | \(30\degree\) or \(0\degree\) |
| Q | If \(n = √3\) and \(\alpha= 180°\), then all the possible values of \(\theta_0\) will be | II | \(60\degree\) or \(0\degree\) |
| R | If \(n = √3\) and \(\alpha= 180°\), then all the possible values of \(\phi_0\) will be | III | \(45\degree\) or \( 0\degree\) |
| S | If \(n = \sqrt2\) and \(\theta_0 = 45°\), then all the possible values of \(\alpha\) will be | IV | \(150\degree\) |
| \[0\degree\] | |||
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
When a light ray falls on any object, it is bounced back from the object. This process is known as the Reflection of light. The light reflected from the object falls into our eyes, making the object visible to us. All the things we see around us are because of reflection.
The reflection of light depends on the type of object. A polished or smooth surface reflects most of the light falling on it, while a rough surface absorbs some amount of light and reflects back the rest of the light. The direction of reflected rays depends upon the surface of the object.