In the given circuit, the rms value of current (\( I_{\text{rms}} \)) through the resistor \( R \) is:
In an AC circuit, the impedance \( Z \) is given by \( Z = \sqrt{R^2 + (X_L -X_C)^2} \), where \( R \) is the resistance, \( X_L \) is the inductive reactance, and \( X_C \) is the capacitive reactance. The rms current can be calculated using \( I_{\text{rms}} = \frac{V_{\text{rms}}}{Z} \).
Step 1: Understanding the Problem
We are given an AC circuit with a resistor \( R = 100\Omega \), inductive reactance \( X_L = 200\Omega \), and capacitive reactance \( X_C = 100\Omega \). The rms voltage \( V_{\text{rms}} = 200\sqrt{2}V \). We need to find the rms current through the resistor.
Step 2: Calculating the Impedance of the Circuit
The impedance (\( Z \)) of the circuit is given by: \[ Z = \sqrt{R^2 + (X_L -X_C)^2}. \]
Substituting the given values: \[ Z = \sqrt{100^2 + (200 -100)^2} = \sqrt{10000 + 10000} = \sqrt{20000} = 100\sqrt{2}\Omega. \]
Step 3: Calculating the rms Current
The rms current (\( I_{\text{rms}} \)) is given by: \[ I_{\text{rms}} = \frac{V_{\text{rms}}}{Z}. \]
Substituting the values: \[ I_{\text{rms}} = \frac{200\sqrt{2}}{100\sqrt{2}} = 2A. \]
Step 4: Matching with the Options
The calculated rms current is \(2A\), which corresponds to option (A). Final Answer: The rms value of current through the resistor is 2A.
The figure shows an opamp circuit with a 5.1 V Zener diode in the feedback loop. The opamp runs from \( \pm 15 \, {V} \) supplies. If a \( +1 \, {V} \) signal is applied at the input, the output voltage (rounded off to one decimal place) is:
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
State Kirchhoff's law related to electrical circuits. In the given metre bridge, balance point is obtained at D. On connecting a resistance of 12 ohm parallel to S, balance point shifts to D'. Find the values of resistances R and S.