Question:
In the following unbalanced reaction, the product formed is:
NaAlO$_2$ + Al(OH)$_3$ + H$_2$O $\rightarrow$ ?
In the following unbalanced reaction, the product formed is:
NaAlO$_2$ + Al(OH)$_3$ + H$_2$O $\rightarrow$ ?
NaAlO$_2$ + Al(OH)$_3$ + H$_2$O $\rightarrow$ ?
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Recognize complex ion formation from amphoteric Al(OH)$_3$
Tetrahydroxoaluminate is a key species in amphoteric behavior
Updated On: May 19, 2025
- Na$_3$[Al(OH)$_6$]
- Na$_2$[Al(OH)$_4$]
- Na[Al(OH)$_4$]
- Na[Al(OH)$_6$]
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The Correct Option is C
Solution and Explanation
- Sodium aluminate reacts with aluminum hydroxide and water:
\[
\text{NaAlO}_2 + \text{Al(OH)}_3 + \text{H}_2\text{O} \rightarrow \text{Na[Al(OH)}_4\text{]}
\]
- This forms a soluble complex ion: tetrahydroxoaluminate (Na[Al(OH)$_4$])
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