Question:

In the following reaction sequence, what are X and Y respectively?
hydrazine (NH2NH2) reacting with the ester

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The Wolff-Löffler reduction can convert esters to hydrazones, followed by base hydrolysis to yield amines.
Updated On: Mar 12, 2025
  • hydrazine (NH2NH2) reacting with the ester
  • \( \text{NH}_2\text{NH}_2 ; \, \text{Zn-Hg}, \, \text{HCl} \)
  • hydrazine (NH2NH2) reacting with the ester
  • \( \text{NH}_2\text{OH} ; \, \text{Zn-Hg}, \, \text{HCl} \)
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The Correct Option is A

Solution and Explanation

In this reaction sequence, the starting material is an ester (ethyl acetate, C6H5COOCH3). The first step involves hydrazine (NH2NH2) reacting with the ester, which undergoes reduction to form hydrazone (X). Subsequent treatment with KOH or water hydrolyzes the hydrazone to form the corresponding amine, which is the final product (Y).
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