- \( Sc^{3+} \) and \( Zn^{2+} \) are both colourless because they have no unpaired electrons in their d-orbitals, which means they do not absorb visible light.
- In other cases like \( V^{2+}, Ti^{3+} \), and \( Ti^{4+}, Cu^{2+} \), the ions have unpaired electrons in their d-orbitals, which are responsible for absorbing light and thus exhibiting colour.
Thus, the correct answer is 4) \( Sc^{3+}, Zn^{2+} \).