Question

In the following network, \(I_1=-0.4\,\text{A}\), \(I_4=1\,\text{A}\) and \(I_5=0.4\,\text{A}\). The values of \(I_2\), \(I_3\) and \(I_6\) respectively are

• A. \(0.4\,\text{A},-0.6\,\text{A},1.4\,\text{A}\)
• B. \(-0.6\,\text{A},1.4\,\text{A},0.4\,\text{A}\)
• C. \(1.4\,\text{A},0.4\,\text{A},-0.6\,\text{A}\)
• D. \(1.4\,\text{A},-0.6\,\text{A},0.4\,\text{A}\)

Hint:

Always apply Kirchhoff’s current law carefully with proper sign convention at each junction.

Answer 1

The Correct Option is D

Step 1: Apply Kirchhoff’s current law at junction.
Sum of currents entering a junction equals sum of currents leaving the junction.

Step 2: Use given current directions and values.
By applying KCL at appropriate nodes and considering sign convention, we obtain: \[ I_2 = 1.4\,\text{A}, \quad I_3 = -0.6\,\text{A}, \quad I_6 = 0.4\,\text{A} \]

Step 3: Interpretation of negative sign.
Negative sign indicates actual direction of current is opposite to the assumed direction.