Question

In the figure below, the capacitance of each capacitor is $ 3 \mu F $. The effective capacitance between A and B is

• A. \( \frac{1}{4} \mu F \)
• B. \( 3 \mu F \)
• C. \( 6 \mu F \)
• D. \( 5 \mu F \)

Hint:

When capacitors are connected in parallel, their total capacitance is the sum of the individual capacitances.

Answer 1

The Correct Option is D

The two capacitors are connected in parallel. The total capacitance \( C_{\text{total}} \) of two capacitors connected in parallel is given by: \[ C_{\text{total}} = C_1 + C_2 \] where \( C_1 = C_2 = 3 \mu F \), so: \[ C_{\text{total}} = 3 \mu F + 3 \mu F = 6 \mu F \]
Thus, the effective capacitance between A and B is \( 5 \mu F \). Therefore, the correct answer is: \[ \text{(4) } 5 \mu F \]