\(188\) g AgBr has \(80\) g of Br
∴ \(0.4\) g AgBr \(=\frac {80}{188} × 0.4\)
% of Br in given organic compound
\(= \frac {80 × 0.4}{188 × 0.5 }× 100\)
≈ 34%
So, the answer is 34%.
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: