\(188\) g AgBr has \(80\) g of Br
∴ \(0.4\) g AgBr \(=\frac {80}{188} × 0.4\)
% of Br in given organic compound
\(= \frac {80 × 0.4}{188 × 0.5 }× 100\)
≈ 34%
So, the answer is 34%.
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: