Question

In the equilibrium, \( AB \rightleftharpoons A + B \), if the equilibrium concentration of A is double, then the equilibrium concentration of B will be:

• A. Half
• B. Twice
• C. \( \frac{1}{4} \)
• D. \( \frac{1}{8} \)

Hint:

When equilibrium concentrations of one reactant change, the equilibrium concentrations of other substances adjust to maintain the equilibrium constant.

Answer 1

The Correct Option is A

In equilibrium reactions, the concentrations of the reactants and products are related by the equilibrium constant. If the concentration of \( A \) is doubled, this means that the amount of \( B \) produced must decrease because of the conservation of mass. Therefore, the equilibrium concentration of \( B \) will be half of the initial concentration of \( B \). Thus, the correct answer is option (A).